What is the correct answer to this simple maths problem?

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The discussion centers on a math problem regarding bus runs, with one participant asserting the total number of runs is 88, while another calculates it as 84. The first calculation includes two morning runs, 71 runs from 8:30 A.M. to 8:30 P.M., and additional runs until 9:14 P.M. The second participant questions the start time for the 10-minute intervals, suggesting it begins at 7:30 A.M. instead of 8:30 A.M., which affects the total count. The ambiguity in interpreting the timing of the bus runs leads to differing conclusions, highlighting the importance of clear problem statements in math.
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http://img372.imageshack.us/img372/2057/timezy9.jpg

See image above. The answer is D - 88, however I can only find 84! Please can someone let me know what I am missing:

20-7= 13
13*6 + 1 = 79 = total upto 2030
+ 2045 bus = 80

+ 4 buses (two in 21st hr, two in 22nd hr) = 84

Thanks
 
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Looks straight forward to me. First there are the two morning runs. Then it runs "every 10 minutes" from 8:30 to 20:30 (8:30 A.M. to 8:30 P.M.). That's 12 hours and 6 times an hour for 12 hours is 72 times- actually 71 since we are counting exactly at 8:30 separately. Then 2 more runs until 21:14 (9:14 P.M.). Then 12 runs between 21:14 and 22:45 culminating in the final run. A total of 2+ 71+ 2+ 12+ 1= 88 runs.
 
Thanks for the reply. Isn't it every 10 minutes from 7:30 to 20:30, not from 8:30 to 20:30, which gives 79 runs up until the 20:30 run. Also, how are there "12 runs between 21:14 and 22:45 culminating in the final run?"

Thanks
 
I was interpreting "then every 10 mins" as meaning from the END of the first two runs. You are interpreting it as 10 min after the start of the second run. I can't say which interpretation is correct.
 
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