What Is the Correct Velocity of a Bungee Jumper as the Cord Begins to Stretch?

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The discussion focuses on calculating the velocity of a bungee jumper, Lola, as she begins to stretch her bungee cord after jumping from a height of 100 meters. Using the equation V=√(k/m)(A)^2, a calculated velocity of 197.20 m/s is presented, but concerns are raised about the accuracy of this high value. It is suggested to disregard the spring's influence initially since Lola is in free fall before the cord stretches. The second part of the question regarding the time to reach this point remains unanswered, indicating a need for further clarification on the appropriate equations to use. The conversation highlights the complexities of bungee jumping physics and the importance of using correct formulas.
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Lola goes bungee jumping. She leaps from a bridge that is 100 m above a river. Her bungee cord has an unstretched length of 50 m and a spring constant k=700N/m. lola has a mass of 45 kg. How fast is she falling when she just starts to stretch the cord? How long does it take for Lola to reach this point.

I used the equation V=√(k/m)(A)^2 and I got

V=√(700N/m/45kg)(50m)^2)=197.20m/s

I was wondering If I used the right equation b/c the answer seems awfully high.

The second part of the question i don't know which equation to use.
Thanks
 
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Just ignore the spring, because it is not being stretched yet. She's just plain old falling.
 

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