What is the Correct Way to Calculate the Period of Io?

AI Thread Summary
To calculate the period of Io, the gravitational force was determined to be 6.334 x 10^22 N using the provided mass and distance values. The equation used for the gravitational force involves the mass of Io and the distance from the center of Jupiter to the center of Io. The key question raised is whether to use the center-to-center distance or to subtract Jupiter's radius from this distance when calculating R. The consensus is to use the center-to-center distance, as the inclusion of Jupiter's radius in the problem is meant to mislead. This highlights the importance of clarity in gravitational calculations.
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[SOLVED] Universal Gravitation

Homework Statement



Jupiter's closest moon, Io has a mass of 8.90 x 10^22 kg. The mean radius of Jupiter is 6.99 x 10^7m, the mean distance from the center of Jupiter to the center of Io is 4.22 x 10^8m, and the mass of Jupiter is 1.90 x 10^27.

A) Determine the gravitational froce
B)Find the period of Io

The Attempt at a Solution



I solved for F_G and got = 6.334 x 10^22

Then I set up my equation like so:

F_G = \frac{m_{Io}4\pi^2(R)}{T^2}

My question is, for R in the above equation would I just use the distance between the center of masses, or the distance between the center of mass minus the radius of Jupiter? I am sure it is the center of masses, but why is Jupiter's radius in the problem then...
 
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Probably to tempt you to make the mistake of NOT using the center to center distance. Resist that temptation.
 
Tricky indeed. Thanks
 
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