What is the correct way to convert a matrix to reduced row echelon form?

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Homework Help Overview

The discussion revolves around the concept of converting a matrix to reduced row echelon form (RREF). The original poster presents a matrix and their attempt at achieving RREF, seeking clarification on their result.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to convert a given matrix to RREF and questions the correctness of their result. Some participants provide feedback on the definition of RREF and point out potential errors in the original poster's calculations.

Discussion Status

Participants are actively engaging in clarifying the requirements for RREF and discussing the correctness of the original poster's calculations. There is a mix of feedback regarding the arithmetic and definitions involved, with no explicit consensus reached on the final form.

Contextual Notes

Participants are addressing specific arithmetic steps and definitions related to matrix transformations, indicating a focus on understanding the underlying principles of RREF.

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What exactly is a reduced row echelon matrix.

I had to convert this to one:
1 2 1 1 1 1
-3 -6 -2 0 -1 -3
2 4 2 1 3 -3

And got:
1 2 1 1 1 1
0 0 1 3 2 0
0 0 0 1 -1 5

Is this right and, if not, why?

Thanks for the help.
 
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Assuming your arithmetic is correct, that is row echelon form. Reduced row echelon form requires that each column with a leading one have nothing else but zeros in it.
 
You have the signs on the last row wrong. You are subtracting 2 times the first row from the third and should have 1- 2(1)= -1, 3- 2(1)= 1, and -3-2(1)= -5.
 
Thanks for the help.

I got
1 2 0 0 3 -11
0 0 1 0 5 -15
0 0 0 1 -1 5

I think this is right.

I did it the other way round HallsofIvy.
 

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