MHB What is the Cost of One Jump Ring in a $8 Pack of 1000?

  • Thread starter Thread starter Enoonmai
  • Start date Start date
  • Tags Tags
    Jump Ring
AI Thread Summary
The cost of each jump ring in an $8 pack of 1,000 is calculated by dividing $8 by 1,000, resulting in 0.008 dollars per ring. This value translates to 0.8 cents per jump ring, which can also be expressed as "one tenth of 8 cents." Another perspective is that it equates to 4 cents for every 5 jump rings. The confusion primarily lies in interpreting 0.008 as either dollars or cents, but it is confirmed to be in dollars. Understanding this calculation clarifies the cost per jump ring effectively.
Enoonmai
Messages
2
Reaction score
0
If I get a pack of 1,000 jump rings (for jewelry), and the bag costs me $8, how much is EACH jump ring? is it 8 divided by 1,000, which is .008 cents per ring, or is this .008 dollars, and I move the decimal spaces two to the left to get cents? I m a bit confused... Thanks!
 
Mathematics news on Phys.org
I would write:

$$\frac{\$8}{1000 \text{ jump rings}}\cdot\frac{100\text{ cents}}{\$1}=\frac{4}{5}\,\frac{\text{cents}}{\text{jump ring}}$$
 
MarkFL said:
I would write:

$$\frac{\$8}{1000 \text{ jump rings}}\cdot\frac{100\text{ cents}}{\$1}=\frac{4}{5}\,\frac{\text{cents}}{\text{jump ring}}$$

Thank you very much! So the .008 was just .008 "dollars" earlier? $8/1000 = 0.008 Dollars?

Is that the same as saying "one tenth of 8 cents per ring" ?
 
Enoonmai said:
Thank you very much! So the .008 was just .008 "dollars" earlier? $8/1000 = 0.008 Dollars?

Is that the same as saying "one tenth of 8 cents per ring" ?

Yes, and another way to look at it is "4 cents for every 5 jump rings."
 
Thread 'Video on imaginary numbers and some queries'
Hi, I was watching the following video. I found some points confusing. Could you please help me to understand the gaps? Thanks, in advance! Question 1: Around 4:22, the video says the following. So for those mathematicians, negative numbers didn't exist. You could subtract, that is find the difference between two positive quantities, but you couldn't have a negative answer or negative coefficients. Mathematicians were so averse to negative numbers that there was no single quadratic...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...

Similar threads

Back
Top