What is the derivative of xy with respect to t, when x=8 and dx/dt=10?

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SUMMARY

The discussion focuses on finding the derivative of the product xy with respect to t, specifically when x=8 and dx/dt=10. The participants emphasize the use of the chain rule to derive dy/dt from the implicit relationship xy=4. The correct approach involves differentiating both sides of the equation with respect to t, leading to the conclusion that dy/dt can be expressed as - (dy/dx) * (dx/dt), where dy/dx is determined from the implicit differentiation of the equation.

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homeylova223
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Hello everyone I have a two question


my first one is differentiate with respect to t

y=x^2-3x find dy/dt when x=3 and dx/dt=2

This is what I did
dy/dt=2x dx/dt (I am stuck right here)


my second one is

xy=4 find dy/dt when x=8 dx/dt=10
 
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homeylova223 said:
Hello everyone I have a two question


my first one is differentiate with respect to t

y=x^2-3x find dy/dt when x=3 and dx/dt=2

This is what I did
dy/dt=2x dx/dt (I am stuck right here)
What is the derivative of -3x with respect to t, in terms of dx/dt?


homeylova223 said:
my second one is

xy=4 find dy/dt when x=8 dx/dt=10

First, solve for y, using the first equation. Then get dy/dt in terms of x and dx/dt using the chain rule.
 

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