What is the difference between friction and rolling resistance?

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Homework Help Overview

The discussion revolves around understanding the concepts of friction and rolling resistance in the context of a cyclist moving uphill on a slope. Participants are exploring how to analyze forces acting on the bicycle and cyclist system, particularly when coefficients of friction are not provided.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants question the necessity of knowing the frictional force to solve the problem and discuss the implications of rolling without slipping. There is a focus on the forces acting on the cyclist and bicycle system, including the applied force and the effects of gravity.

Discussion Status

Some participants have offered guidance on focusing on the forces relevant to the problem rather than on frictional forces that may not apply. There is recognition of a common confusion between friction and rolling resistance, with suggestions to clarify these concepts further.

Contextual Notes

There is an emphasis on the specific conditions of the problem, such as the cyclist's uphill movement and the rate of deceleration, which may influence the interpretation of forces involved. Participants are encouraged to consider the problem's context and the assumptions being made.

paulimerci
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Poster has been reminded to always show their work when posting schoolwork problems
Homework Statement
A 65 kg cyclist on a 10 kg bicycle is moving uphill on a 9° slope. How much force does he provide
if the bicycle slows at a rate of 0.3 m/s2?
Relevant Equations
Applied force - frictional force - parallel force component due to gravity = ma
How to find frictional force when coefficient of friction is not given?
 

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If the bicycle wheels roll without slipping or are not on the verge of slipping, the coefficients of friction are irrelevant. You have the acceleration, so what is the net force on the bicycle + cyclist system? What is the net force just on the bicycle?
 
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So you mean there is no frictional force acting on the system?
 
paulimerci said:
So you mean there is no frictional force acting on the system?
Not what he means.

He said that you don't need to know the frictional force to solve this problem.
 
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SammyS said:
Not what he means.

He said that you don't need to know the frictional force to solve this problem.
But it’s asking for the force the rider provides, not the net force.

I feel like “ignore friction” should be right in the problem statement on this one?
 
Last edited:
paulimerci said:
Homework Statement:: A 65 kg cyclist on a 10 kg bicycle is moving uphill on a 9° slope. How much force does he provide
if the bicycle slows at a rate of 0.3 m/s2?
Relevant Equations:: Applied force - frictional force - parallel force component due to gravity = ma

How to find frictional force when coefficient of friction is not given?
@paulimerci -- Please post a new thread with this problem and show your work.

As you can see from the replies, this is most likely not a problem of something sliding up or down an inclined plane with sliding friction coming into play. If a bicyclist is pedaling up a slope and slowing down, there is a force that the bicyclist is applying by pedaling but it's not enough force to keep them from slowing down on the slope. So in your FBD, you should leave off any retarding force due to sliding friction, and focus on what force the bicyclist needs to exert to result in the motion specified in the problem.
 
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Disregard post #5. I think I see what @kuruman was driving at now that I've written it down.
 
paulimerci said:
Homework Statement:: A 65 kg cyclist on a 10 kg bicycle is moving uphill on a 9° slope. How much force does he provide
if the bicycle slows at a rate of 0.3 m/s2?
Relevant Equations:: Applied force - frictional force - parallel force component due to gravity = ma

How to find frictional force when coefficient of friction is not given?
You are suffering from a common confusion between friction and rolling resistance. The relevant equation posted takes friction as always something opposing motion, which is incorrect.
Please read https://www.physicsforums.com/insights/frequently-made-errors-mechanics-friction/ before reposting the thread .
 
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