What is the difference between friction and rolling resistance?

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SUMMARY

The discussion clarifies the distinction between friction and rolling resistance in the context of a cyclist moving uphill. It emphasizes that when a bicycle rolls without slipping, the coefficients of friction are irrelevant to the problem at hand. The key equation provided is: Applied force - frictional force - parallel force component due to gravity = ma. The participants agree that the frictional force does not need to be considered for calculating the force exerted by the cyclist, especially when the bicycle is slowing down on an incline.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with free body diagrams (FBD)
  • Knowledge of forces acting on inclined planes
  • Basic grasp of rolling resistance concepts
NEXT STEPS
  • Study the differences between static friction, kinetic friction, and rolling resistance
  • Learn how to construct and analyze free body diagrams for inclined planes
  • Research the effects of slope angle on force calculations in cycling
  • Explore the role of coefficients of friction in various motion scenarios
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the mechanics of cycling, particularly in relation to forces acting on bicycles on slopes.

paulimerci
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Poster has been reminded to always show their work when posting schoolwork problems
Homework Statement
A 65 kg cyclist on a 10 kg bicycle is moving uphill on a 9° slope. How much force does he provide
if the bicycle slows at a rate of 0.3 m/s2?
Relevant Equations
Applied force - frictional force - parallel force component due to gravity = ma
How to find frictional force when coefficient of friction is not given?
 

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If the bicycle wheels roll without slipping or are not on the verge of slipping, the coefficients of friction are irrelevant. You have the acceleration, so what is the net force on the bicycle + cyclist system? What is the net force just on the bicycle?
 
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So you mean there is no frictional force acting on the system?
 
paulimerci said:
So you mean there is no frictional force acting on the system?
Not what he means.

He said that you don't need to know the frictional force to solve this problem.
 
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SammyS said:
Not what he means.

He said that you don't need to know the frictional force to solve this problem.
But it’s asking for the force the rider provides, not the net force.

I feel like “ignore friction” should be right in the problem statement on this one?
 
Last edited:
paulimerci said:
Homework Statement:: A 65 kg cyclist on a 10 kg bicycle is moving uphill on a 9° slope. How much force does he provide
if the bicycle slows at a rate of 0.3 m/s2?
Relevant Equations:: Applied force - frictional force - parallel force component due to gravity = ma

How to find frictional force when coefficient of friction is not given?
@paulimerci -- Please post a new thread with this problem and show your work.

As you can see from the replies, this is most likely not a problem of something sliding up or down an inclined plane with sliding friction coming into play. If a bicyclist is pedaling up a slope and slowing down, there is a force that the bicyclist is applying by pedaling but it's not enough force to keep them from slowing down on the slope. So in your FBD, you should leave off any retarding force due to sliding friction, and focus on what force the bicyclist needs to exert to result in the motion specified in the problem.
 
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Disregard post #5. I think I see what @kuruman was driving at now that I've written it down.
 
paulimerci said:
Homework Statement:: A 65 kg cyclist on a 10 kg bicycle is moving uphill on a 9° slope. How much force does he provide
if the bicycle slows at a rate of 0.3 m/s2?
Relevant Equations:: Applied force - frictional force - parallel force component due to gravity = ma

How to find frictional force when coefficient of friction is not given?
You are suffering from a common confusion between friction and rolling resistance. The relevant equation posted takes friction as always something opposing motion, which is incorrect.
Please read https://www.physicsforums.com/insights/frequently-made-errors-mechanics-friction/ before reposting the thread .
 
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