What is the Direction of an Emu's Acceleration When Slowing Down?

  • Thread starter Thread starter shawonna23
  • Start date Start date
  • Tags Tags
    Acceleration
AI Thread Summary
The emu, initially running due south at 13.9 m/s, decelerates to 10.5 m/s over 2.7 seconds, indicating negative acceleration directed north. This deceleration signifies that the acceleration vector opposes the direction of motion. To find the emu's velocity after an additional 3.9 seconds, the same negative acceleration can be applied. The calculations suggest that the emu continues to slow down, resulting in a final velocity lower than 10.5 m/s. Understanding the relationship between velocity and acceleration is crucial in determining the bird's motion.
shawonna23
Messages
146
Reaction score
0
help please! Problem on Acceleration

The land speed record of 13.9 m/s (31 mi/h) for birds is held by the Australian emu. An emu running due south in a straight line at this speed slows down to a speed of 10.5 m/s in 2.7 s.

What is the direction of the bird's acceleration?

Assuming that the acceleration remains the same, what is the bird's velocity after an additional 3.9 s has elapsed?
 
Physics news on Phys.org
Hint:

a=\frac{v_f-v_i}{t}
 
Hint: If it slows down it is decelerating i.e negative acceleration
 
Also, "speeding up" means speed is increasing: acceleration is "positive"- in same direction as velocity.

"Slowing down" means speed is decreasing: acceleration is "negative"- in opposite direction to velocity.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top