What is the direction of the E field at point P due to the sphere?

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The discussion revolves around calculating the electric field intensity at point P, located at x=1 m and y=0.5 m, due to a charged infinite plane and a sphere. The electric field from the plane is calculated as Eplane = -113 kN/C in the negative i direction. To find the electric field from the sphere, the formula E = (4/3)πkrρr̂ is mentioned, but the user needs assistance determining the unit vector r̂. The hint suggests using Gauss's law to simplify the calculations. The overall goal is to combine the electric fields from both sources to find the total intensity at point P.
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Homework Statement


an infinite plan,parallel to the yz plan which passes from x=2 meter, is charged equally with the σ= 2μC/m^2 .A sphere with a radius 0.8 meters has its center in the in x=1 m,y=0 and has ρ=-6μC/m^3.Find the value of the intensity of the electric field in the point x=1 m and y=0.5 m.



Homework Equations


the figure :
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The Attempt at a Solution


The E at P is = Eplane + Esphere
I find the E of plane =(-σ/2∈ )* i=-113kN/C * i
To find the E of sphere, I have to use the formula E=(4*pi/3)*k*r*ρ*rˆ... I have every known data,I just need to find the unit vector r or (rˆ)..how to find it?
 
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By symmetry, what is the direction of the E field at point p due to the sphere by itself?
Hint: invoke Gauss's law.
 
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