What is the Direction of Total Force Acting on an Object?

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To determine the direction of the total force acting on a 5 kg object with forces F1 and F2, vector addition is necessary. F1 is 25 N at 0 degrees, while F2 is 15 N at 60 degrees counterclockwise from the x-axis. The x components are calculated by adding 25 N and 15 N multiplied by the cosine of 60 degrees, while the y components involve the sine of 60 degrees. The resultant angle of the total force can then be found using the arctangent of the ratio of the y component to the x component. This method provides a clear approach to finding the resultant direction of the forces.
Rileyss123
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This is a fairly simple Question but I just can't figure it out. If there is an object and there are two forces that act on the 5 kg object (say this object is located on the origin of an sy plane) and F1= 25 N and points in the 0 degrees direction and the other force, F2= 15 N and points 60 degrees counterclockwise from the x axis/ F1, what would be the direction of the total force counterclockwise from the x axis??

THANK YOU
 
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Do you know how to do vector addition? If so, then this question is simple. You can, in fact, add up the x and y components separately:

x components:

(25 N) + (15 N)cos(60 deg)

y components

0 + (15 N)sin(60 deg)

So what angle does the resultant vector make with the x-axis?
 
Thanksss
 
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