What is the Distance Between Two Photons in Different Reference Frames?

AI Thread Summary
The discussion centers on calculating the distance between two photons traveling along the x-axis in different reference frames, specifically proving that the distance is L(c+v)^(1/2)/(c-v)^(1/2). Participants emphasize the importance of simultaneity, noting that distances must be measured at the same time in the moving frame (S') rather than the stationary frame (S). The use of spacetime diagrams is recommended as a helpful tool for visualizing the problem. There is confusion regarding the application of length contraction and the correct approach to finding the coordinates of the photons in the moving frame. The conversation highlights the nuances of special relativity and the need for careful consideration of reference frames.
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Homework Statement



two photons travel along the x-axis of S , WITH A CONSTANT DISTANCE L betweenthem. Prove that in S's the distance between these photons is L(c+v)^1/2/(c-v)^1/2.

Homework Equations




x'=gamma*(x-vt), x=gamma*(x'+vt), t=gamma*(t'+vx'/c^2), t=gamma*(t'-vx'/c^2)

The Attempt at a Solution



L(c+v)^1/2/(c-v)^1/2=L((c+v)/(c-v))^.5=L((+v/c)/(1-v/c))^.5. So will the two photons reach a midpoint along the x-axis. I think I should either find the difference between x_2 and x_`1 or the difference between x'_1 and x'_2. I thinkl in one reference frame , the time would be dilated with the moving frame for both photons . Is my line of thinking correct?
 
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noblegas said:
or the difference between x'_1 and x'_2.
That is the quantity you should be looking for, keeping in mind that the definition of simultaneity is not the same in S' as in S - so you need to calculate the difference between x_1' and x_2' as measured at the same time in S', not at the same time in S.

Consider drawing a spacetime diagram. I find that doing that helps with these kinds of problems.
 
diazona said:
That is the quantity you should be looking for, keeping in mind that the definition of simultaneity is not the same in S' as in S - so you need to calculate the difference between x_1' and x_2' as measured at the same time in S', not at the same time in S.

Consider drawing a spacetime diagram. I find that doing that helps with these kinds of problems.

In order to calculate x_2' and x_1' should I calculate t_1 and t_2 first?
 
I'm trying to teach myself special relativity (using the book 'Introduction to Special Relativity' by Wolfgang Rindler). I'm currently working on the problem stated above.

My first approach was : x1=ct ; x2=L+ct.
Then using x'=gamma(x-vt) and t'=gamma(t-vx/c²) I calculate x1' and x2'. However I'm always arriving at L'=gamma(L) which is the formula for Length contraction.

Where is my mistake ? There obviously is a difference between the length contraction (of a rod in S seen from S') and the 'length contraction' in this problem (the distance between 2 moving photons).
 
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