What is the distance the projectile lands from the base of the cliff?

AI Thread Summary
To determine the distance the basketball lands from the base of the cliff, the horizontal velocity (vix) of 25 m/s is crucial, as it directly affects horizontal displacement. Given that the time of flight is 8 seconds, the horizontal distance can be calculated using the formula: distance = velocity x time. Thus, the basketball travels 25 m/s multiplied by 8 seconds, resulting in a distance of 200 meters from the base of the cliff. The vertical velocity (viy) is not needed for this specific calculation. The projectile lands 200 meters away from the cliff's base.
kenji1992
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Homework Statement


A basketball, thrown off a cliff with a velocity of (30.0, 25.0) m/s, lands on the ground 8.00 s later. In the absence of air resistance, what is the distance the projectile lands from the base of the cliff?

Homework Equations



http://www.ux1.eiu.edu/~cfadd/1150/03Vct2D/proj.html
I found these equations online, but I don't know I should use them.

The Attempt at a Solution



viy=30 m/s
vix=25 m/s
t=8 s
d=?
 
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Think about what vix and viy mean. How do they relate to the figures given in your attachment? Which one would be more helpful in calculating how far from the base of the cliff the basketball travels in 8 sec.?
 

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