What is the domain of a trig function with y = 2sin(x)?

AI Thread Summary
The function y = 2sin(x) has a range of -2 to 2, as derived from the sine function's properties. The domain of the function is specified as -π < x ≤ π. To demonstrate the function's behavior, one can find the x-values that yield the maximum and minimum outputs of -2 and 2, confirming they fall within the domain. The periodic nature of the sine function, with a period of 2π, ensures that all values between -2 and 2 are covered within the specified domain. This approach, along with graphing the function, effectively illustrates its characteristics.
so_gr_lo
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Homework Statement
I am supposed to find the limits of a trig function, which I have managed to do, but I don’t know how to show that the range can be achieved within the given domain.
Relevant Equations
y = 2sin(x)
y = 2sin(x)

-1≤ sin(x) ≤ 1

-2 ≤ 2sin(x) ≤ 2

so -2 and 2 are the max/min limits

but the domain is -π < x ≤ π

Do I find the values of x that outputs -2 and 2 and show that they are within the domain ?
 
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2sin x has period ##2\pi## so both the minimum and the maximum value are realized in the domain. Draw the graph.
 
so_gr_lo said:
Do I find the values of x that outputs -2 and 2 and show that they are within the domain ?
That is a good approach. Then use the continuity of the function to say that it covers everything in between.
 
yeah I think that might be what is expected, thanks
 
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