What is the efficiency of the engines?

AI Thread Summary
The discussion focuses on calculating the efficiency of an aircraft's engines based on its ascent to cruising altitude. The aircraft weighs 3250 kg and takes 12.5 minutes to reach 10 km while traveling at a cruising speed of 850 km/h. The power output is calculated using the average velocity and mass, while the power input is derived from the engine's horsepower converted to watts. The efficiency is determined to be approximately 48.7%, although there is confusion regarding the calculation methods and the correct application of physics equations. The conversation highlights the importance of understanding the relationship between power output, power input, and efficiency in aviation engines.
Lyphta
Messages
11
Reaction score
0

Homework Statement


A 3250 km aircraft takes 12.5 minutes to achieve its cruising altitude of 10 km and cruising speed of 850 km/h. If the plane's engines deliver, on the average, 1500 hp of power during this time, what is the efficiency of the engines?


Homework Equations


Efficiency = Power output / Power input x 100
P = W/t --> P= mgh/t, P=Fdcos(theta)/t



The Attempt at a Solution


m = 3250 kg
t = 12.5 min --> 750 sec
h = 10 km --> 10000 m
Pin = 1500 hp --> 1119000 Watts
v = 850 km/h --> 236.11 m/s

vf = at +vi (attempt to find the velocity components but don't add up right)
236.11 = a (750) + 0
a = .315 m/s^2

average v = vf/2
= 236.11/2
average v = 118 m/s

Poutx = F(average v) = ma(average v)
= 3250(.315)(118)
= 120802.5 W

Piny = Fd/t = mgh/t
= 3250(9.81)(10000)/750
= 425100 W

The real answer is 4.091 x 10^8 J ; e = 48.7% but I don't know how to get that answer...
 
Physics news on Phys.org
Acceleration can be found by v^2 = u^2 + 2as. This acceleration is in addition to the acceleration due to gravity. So the actual acceleration of the aircraft is a+g. Now find the work done.
 
by u, do you mean initial velocity? or potential energy?
 
It is initial velocity, which is zero in this case.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top