What is the equation for finding the mass of an ion using a mass spectrometer?

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To find the mass of a singly charged ion using a mass spectrometer, the relevant equation is m = (qB^2r^2)/2V. In this case, the voltage (V) is 2.00 kV, the magnetic field (B) is 0.400 T, and the radius (r) is 0.305 m. The charge (q) of the ion is +e, which is approximately 1.602 x 10^-19 C. After substituting the correct values into the equation, the mass can be calculated correctly. It's important to remember that the charge should be treated as positive in this context.
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Homework Statement


A mass spectrometer applies a voltage of 2.00 kilovolts to accelerate a singly charged ion (+e). This ion then enters a region of uniform magnetic field (B= 0.400 T) which then bends the ion into a circular path of radius 0.305 m What is the mass of the ion?


Homework Equations


after breaking everything down from F=ma i got to m = (qB^2r^2)/2V


The Attempt at a Solution


well i am just unsure of how to find q. I know that V=2kV, B=.4 T, and r=.305 m. so if you can just help me with finding q. i can do that rest
 
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ok well so i tried doing the m= -1.602x10^-19(.4^2)(.305^2)/4 and got -5.96x10^-22. would it be in kg though?
 
shimizua said:
ok well so i tried doing the m= -1.602x10^-19(.4^2)(.305^2)/4 and got -5.96x10^-22. would it be in kg though?

To put it in perspective for a single proton:
Wikipedia said:
1.672621637(83)×10−27 kg
 
The conundrum you got going here is that the charge is +e, not e. SOO...in taking your big step in finally realizing that q is given as the charge +e, you can now go figure that the charge is POSITIVE (1.6*10^-19 C), not negative.
 
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