What is the equation to solve for muzzle speed in a ballistic pendulum problem?

AI Thread Summary
The discussion focuses on calculating the muzzle speed of a bullet using a ballistic pendulum setup, where a bullet strikes a rod and becomes embedded. The equation typically used for this calculation is v0=(M+m)√(2gL(1-cosθ))/m, but there are issues with applying it directly due to the bullet hitting the rod at its center of mass. Participants suggest that the formula may need adjustment, particularly regarding the placement of the square root and the effective length used in the calculations. It is emphasized that understanding the derivation of the formula is crucial for accurate application. Proper adjustments to the equation are necessary to obtain the correct muzzle speed.
scheng12
Messages
3
Reaction score
0

Homework Statement



During a summer internship with a company, you devised the following method of measuring the muzzle speed of a high-powered rifle, as shown in the figure. You fire a bullet into a rod of mass 5.5 kg and length 150 cm that is free to rotate about the pivot at the top. The bullet, whose mass is 8.55 g, strikes at the center of mass of the rod and remains embedded. You measure the maximum opening angle to be 11.5 degrees. What is the muzzle speed in m/s?

Homework Equations


I know the equation to solve for the muzzle speed for a normal ballistic pendulum is

v0=(M+m)\sqrt{}2gL(1-cos\vartheta)/m

The Attempt at a Solution


When I plug the values in the answer comes out to be false since the bullet hits the rod in the center, instead of at the tip. I also tried to plug in L/2 but that doesn't work either. Any ideas?
 
Physics news on Phys.org
any1?
 
Instead of just applying the formula you might want to consider where the formula comes from.

A simple energy relationship will tell you that your square root is in the wrong place.

L = L(overall)/2 this is correct.
 
where is the square root supposed to be?
 
The square root should be over everything on the right hand side.
 
Thread 'Help with Time-Independent Perturbation Theory "Good" States Proof'
(Disclaimer: this is not a HW question. I am self-studying, and this felt like the type of question I've seen in this forum. If there is somewhere better for me to share this doubt, please let me know and I'll transfer it right away.) I am currently reviewing Chapter 7 of Introduction to QM by Griffiths. I have been stuck for an hour or so trying to understand the last paragraph of this proof (pls check the attached file). It claims that we can express Ψ_{γ}(0) as a linear combination of...
Back
Top