What Is the Equilibrium Concentration of CO in the Reaction at 400K?

AI Thread Summary
The discussion centers on calculating the equilibrium concentration of CO in the reaction CO(g) + NH3(g) → HCONH2(g) at 400 K, given an equilibrium constant K of 0.207. The initial concentrations are 2.20 M for CO and 2.60 M for NH3. Participants work through the equation 0.207 = (X) / (2.20-X)(2.6-X) to find the value of X. After analyzing the roots of the rearranged equation, they determine that the valid solution is 1.76, leading to an equilibrium concentration of CO at 0.44 M. The final result indicates that the concentration of CO at equilibrium is 0.44 M.
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Homework Statement



CO(g) + NH_3(g) ...> HCONH_2(g)

euilibrium constant is: K = 0.207 at 400 K
If a reaction is filled with intial concentrations 2.20 M of CO and 2.60 M of NH_3 and the reactanats are allowed to raect at 400K/ what will be the concentrations of CO at equilibrium ?


Homework Equations



Keq = [HCONH_2] / [CO] [NH_3]

The Attempt at a Solution




0.207 = (X) /(2.20-X)(2.6-X)

But I'm getting the wrong answer for x. Please help me.
 
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^your equation for x seems correct. i rearranged it to
0 = 5.72/x - 5.007 + x
we need to find the zeroes

when graphed, the zeros are 1.76 and 3.24

if we use 3.24, we would have a negative concentration of both CO and NH3, which is physically impossible. so, we go with 1.76

so the answer: 2.2 M - 1.76 = 0.44 M
 
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