What is the Equivalence Class for the given Equivalence Relation?

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Homework Help Overview

The discussion revolves around finding the equivalence class [2] for specified equivalence relations involving integers and natural numbers. The first relation involves absolute values of integers, while the second relates to modular arithmetic with natural numbers.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore how to determine equivalence classes based on given relations, questioning the formation of classes and the implications of absolute values and modular arithmetic.

Discussion Status

Participants are actively engaging with the concepts, with some expressing confusion about the equivalence class definitions and the differences in class sizes. Guidance has been offered regarding the nature of equivalence relations and how to express classes, but no consensus has been reached on all aspects.

Contextual Notes

There is uncertainty regarding the notation for the floor function and how to represent equivalence classes that include real numbers. Participants are also reflecting on their understanding of the theory behind equivalence relations, particularly in relation to examples provided in class.

arnold28
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Homework Statement


Find the equivalence class [2] for the following equivalence relations:

a) R: Z <-> Z, where xRy, iff |x| = |y|

b) T: N <-> N, where xTy, iff xmod4 = ymod4

N means natural numbers etc...there wasnt the correct symbols in the latex reference

Homework Equations



??

The Attempt at a Solution



Ok so I know how to do the b) part, because we had examples at the class, its:

[0] = {0,4,8,12,...}
[1] = {1,5,9,13,...}
[2] = {2,6,10,14,...}

so the answer is [2] = {2,6,10,14,...} right?

but i don't know how i start to build it when i have |x| = |y|
its probably something very easy and i just don't get it for some reason
 
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Suppose x is given but unknown, and that |x| = |y|. What can y equal in terms of the given x?
 
hmmm...y must always be +x or -x?
but i don't understand how the classes are formed. For example class [0], does it mean the list starts at 0? In the b-part the list increases always by 4, but what about in this, by 1?
 
Now think about concrete examples. If x = -3, what can y be? Consequently, what is [-3]?
 
if x = -3, then y can then be 3 or -3
What is [-3]? I don't know, {..., ?, -3, ?, ...}
 
Do you understand why the answer to b) is the answer to b)? Back to a).

[x] = {y | xRy} = {y in Z | |y| = |x|}

[-3] = {y | (-3)Ry} = {y in Z | |y| = |-3|}
 
arnold28 said:
if x = -3, then y can then be 3 or -3
What is [-3]? I don't know, {..., ?, -3, ?, ...}
Yes, if |x|= |y| and x= -3, then y can be either 3 or -3. So the only numbers equivalent to -3 are 3 and -3. [-3] is the set[\b] of all numbers equivalent to -3 so [3]= ?
 
I thought I understood the b) part, but now I am not sure if i do deeply enough.

So, in each class the elements are "equivalent" in the way the equivalence relation is defined? xmod4 = ymod4 means every element which has same modulus when divided by 4 belong to same class?

can [-3] then be only {-3,3} in the a) -part?
And [-2] = {-2,2} etc?

I'm confused because we only had those modulus examples in the class and in book and I don't think I understood the theory deeply enough =)
 
Last edited:
arnold28 said:
I thought I understood the b) part, but now I am not sure if i do deeply enough.

So, in each class the elements are "equivalent" in the way the equivalence relation is defined? xmod4 = ymod4 means every element which has same modulus when divided by 4 belong to same class?

Yes.
arnold28 said:
can [-3] then be only {-3,3} in the a) -part?
And [-2] = {-2,2} etc?

Yes.
arnold28 said:
I'm confused because we only had those modulus examples in the class and in book and I don't think I understood the theory deeply enough =)

It looks like you are catching on. :smile:

What about [0] in a)?
 
  • #10
[0] must then be only {0}

What about R: R <-> R, where xRy, iff floor(x) = floor(y)

i don't know if floor() is the right way to write floor function, but can't find the correct symbol. [2] is then something like {2, 2.1, 2.2, ... , 2.99999...} but what is the correct way to write it? Because 2 can have any amount of decimals after it. Does it have to be in a list form like a) and b) here was?

Thanks much for the replies, you helped me a lot!
 
  • #11
arnold28 said:
[0] must then be only {0}[/qu0te]

This shows that different equivalence classes for the same equivalence relation don't have to have the same number of elements, i.e., in a), [-3] has two elements and [0] has one element.

arnold28 said:
What about R: R <-> R, where xRy, iff floor(x) = floor(y)

i don't know if floor() is the right way to write floor function, but can't find the correct symbol. [2] is then something like {2, 2.1, 2.2, ... , 2.99999...} but what is the correct way to write it? Because 2 can have any amount of decimals after it. Does it have to be in a list form like a) and b) here was?

No, it doesn't have to be a list. For example, you can specify [2] by using inequalities.
 

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