What is the final velocity of a particle in a force field around point O?

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24forChromium
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A force field is maintained around point O, a particle with mass m is experiencing a force F in the force field. F as a function of the particle's distance from O is: F = cos(d/5) How does one go about looking for the final velocity of the particle if it began at rest at a negligible distance away from point O?
 
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Calculate the work done on the particle by the force in moving it to distance d away from O. Then find the velocity at which the mass has that kinetic energy.
 
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andrewkirk said:
Calculate the work done on the particle by the force in moving it to distance d away from O. Then find the velocity at which the mass has that kinetic energy.
Absolutely. That is the way to go. The only question I have is, what exactly does the statement of the problem mean by the word, "negligible distance".?
 
In practice it means you can use zero as the lower limit for your integration. I expect the reason they said 'negligible distance' rather than 'start at O' is that usually when forces are symmetrically arranged around a point it's because there's a particle at that point, and two particles can't occupy the same point in classical phycics.
 
andrewkirk said:
In practice it means you can use zero as the lower limit for your integration. I expect the reason they said 'negligible distance' rather than 'start at O' is that usually when forces are symmetrically arranged around a point it's because there's a particle at that point, and two particles can't occupy the same point in classical phycics.
Ah! So the particle is moving effectively from 0 to d?