What is the final velocity of the two balls in an elastic collision?

AI Thread Summary
In an elastic collision problem, a 5 kg ball moving at 2 m/s collides with a stationary 7.5 kg ball, and the goal is to find their final velocities. The conservation of momentum and kinetic energy equations are set up, but an arithmetic mistake occurs in squaring a binomial during calculations. The correct cross term should be -6v_2f, not -3v_2f, leading to an incorrect final velocity for the second ball. After correcting this mistake, the final velocities can be accurately determined. Proper attention to detail in calculations is crucial for solving physics problems like this one.
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Homework Statement



I can't believe I cannot get this! I am trying to help out my gf with this problem:

A 5 kg ball moving at 2 m/s to the right collides with a 7.5 kg stationary ball. If the collision is elastic, what are the final velocities of the 2 balls?

Homework Equations



Momentum is Conserved
KE is conserved


The Attempt at a Solution



Momentum

(m_1v_1)_o+(m_2v_2)_o = (m_1v_1)_f+(m_2v_2)_f

\Rightarrow (5)(2) + (7.5)(0) = 5v_{1f} + 7.5v_{2f}

v_{1f} = 2 - 1.5v_{2f} \qquad (1)

Energy

0.5(m_1v_1^2)_o+0.5(m_2v_2^2)_o = 0.5(m_1v_1^2)_f+0.5(m_2v_2^2)_f

\Rightarrow (5)(2)^2 = 5v_{1f}^2 + 7.5v_2f}^2

v_{1f} = \sqrt{4 - 1.5v_{2f}^2} \qquad (2)


From (1) and (2), we have

2 - 1.5v_{2f} = \sqrt{4 - 1.5v_{2f}^2}

\Rightarrow 4 - 3v_{2f} + 2.25v_{2f}^2 = 4 - 1.5v_{2f}

\Rightarrow 3.75v_{2f}^2 - 3v_{2f} = 0 = (3.75v_{2f} - 3)v_{2f}

\Rightarrow v_{2f} = 0.8 m/s

Which is incorrect.

What the heck am I missing? I feel like such an amateur right now! :redface:
 
Physics news on Phys.org
It's a simple arithmetic mistake... you didn't square the binomial correctly in...

(2 - 1.5v_2f) ^ 2

the cross term is -6v_2f not -3v_2f.
 
Elvex said:
It's a simple arithmetic mistake... you didn't square the binomial correctly in...

(2 - 1.5v_2f) ^ 2

the cross term is -6v_2f not -3v_2f.

Oh jeesh...thank you Elvex!
 
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