What is the force exerted by an object on a rope?

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The discussion revolves around a scenario where a man pulls an object via a rope on a frictionless surface, raising questions about the forces involved and the resulting velocities when they meet. The net force equations are established, showing that the tension in the rope and the forces acting on both the man and the object are equal and opposite. The concept of center of mass is introduced, indicating that both the man and the object will meet at this point due to their respective accelerations. The kinematic equations are suggested for calculating their final velocities, starting from rest. The inquiry concludes with a clarification on whether the forces acting on both the man and the object can be considered equal.
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Homework Statement


Man with mass M pulling with constant horizontal force F along a rope attached to object with mass m. Both the man and the object are on a frictionless surface and separated by distance D. When the man and object meet, what is the velocity of the object? Velocity of the man?


Homework Equations





The Attempt at a Solution


Fnet = ma
Assume motion inwards is positive.
T - F = Ma(subM)
T - F(subobject) = ma(object)

When I draw the free body diagram, what force does the object exert on the rope? How can I "classify" this force? There's no friction, so where would the force of the object come from?
 
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Since there is no external force acting on the system, the center of mass remains at rest.
Let r1 be the distance of M from c.m., and r2 be the distance of m from c.m. such that
Mr1 = mr2. And r1 + r2 = D.
Both man and mass experience equal and opposite force F.
The acceleration of man is a1 = F/M, and acceleration of mass is a2 = F/m. They meet at c.m.
Man and mass start from rest. So vi = 0.
Now using kinematic equation find v1 and v2.
 
Thanks, I wasn't sure if I could say the force on the man and force on the object both equal F.
 
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