What is the force exerted on the Deligne Dam by water pressure?

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(1 pt) The Deligne Dam on the Cayley River is built so that the wall facing the water is shaped like the region above the curve y=0.7 x^2 and below the line y= 300. (Here, distances are measured in meters.) The water level is 38 meters below the top of the dam. Find the force (in Newtons) exerted on the dam by water pressure. (Water has a density of 1000 kg/m^3, and the acceleration of gravity is 9.8 m/sec^2 .)

please help with this problem. I've been working on it every which way I can and my integrals STILL WRONG. URGH!

as well as this problem :
(1 pt) A trough is 7 feet long and 1 foot high. The vertical cross-section of the trough parallel to an end is shaped like the graph of y=x^{4} from x=-1 to x=1 . The trough is full of water. Find the amount of work in foot-pounds required to empty the trough by pumping the water over the top. Note: The weight of water is 62 pounds per cubic foot.

PLEASE PLEASE PLEASE. Thanks!
 
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If you've been working on it "every which way", tell us what you have done so that we CAN help you.
 
(1000 * 9.8 ) * integral of (sqrt(y*4/0.7)(300-y)*dy) from 300 to 0 <--that is wrong...i also don't what to use as my d? for pdg
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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