What is the Force on a Rectangular Loop in a Magnetic Field?

AI Thread Summary
The discussion focuses on calculating the net force on a rectangular loop of wire in a magnetic field created by two currents, I1 and I2. The calculated forces on the loop are F1 and F2, resulting in a net force of approximately -1.35x10-3N directed downwards. Participants express confusion over a potential mistake indicated by the grading system, but they agree on the calculations and reasoning regarding the induced current and emf. The consensus is that the reasoning for the induced emf is correct, and the results align with expectations despite the grading error. Overall, the participants confirm their calculations and understanding of the magnetic interactions involved.
fogvajarash
Messages
127
Reaction score
0

Homework Statement


Let d = 0.048m, L = 0.15m, r = 0.10m in the following diagram. Assume that the current I1 = 80.0A and I2 = 40.0A. Find the net force on the rectangle of wire and the direction it points, and state the direction of the emf if the current I1 is increasing in the direction of the arrow.

Diagram: http://imgur.com/RmvkO9n

Homework Equations


-


The Attempt at a Solution


I have that the force is given by F = BIl. In this case, B would come from the field created by the current I1. So, we would get that the force will be (let force 1 be for the closest part of the loop and force 2 for the farthest part of the loop):

F1 = \frac{μI<sub>2</sub>I<sub>1</sub>l}{2πd} ≈ -2x10-3N
F2 = \frac{μI<sub>2</sub>I<sub>1</sub>l}{2π(d+r)} ≈ 6.49x10-4N

Then, the net force would be Fnet = -1.35x10-3N, pointing downwards. However, I get a mistake. Why is this the case? I'm thinking that my procedure is right until now, as there will be no force felt by the loop wires perpendicular to the long wire. I tried to perhaps calculate an induced current, but I can't do so as I don't have a resistance.

For the second part, the current would be induced to even out the flux change, so the induced B field should point down, leading to an opposite direction of the induced current as stated in the diagram. This is because the flux of the long wire would be increasing upwards in the plane of the wire.
 
Last edited:
Physics news on Phys.org
Hi foggy, I can't see the diagram you are referring to !
 
BvU said:
Hi foggy, I can't see the diagram you are referring to !

So sorry! I have uploaded it right now.
 
I would expect B to be smaller at r+d than at d, so |F| too. Wouldn't you ?

I suppose the -3 is really a -4 ?

How do you know you get a mistake ?

With ##\mu = 4\pi 10^{-7}## I get the same as you...
 
Last edited:
BvU said:
I would expect B to be smaller at r+d than at d, so |F| too. Wouldn't you ?

I suppose the -3 is really a -4 ?

How do you know you get a mistake ?

With ##\mu = 4\pi 10^{-7}## I get the same as you...

My bad again sorry. The computer system is telling me that I have made a mistake (I'm not sure where though). In the meantime, is my reasoning for the flux current correct? Thanks for your time and patience.
 
Well, as I said, same result: same value, same direction.

Your reasoning for the induced emf is right, too. Since they don't tell us how the I2 comes about, there isn't much more that can be said about the effects.
 
BvU said:
Well, as I said, same result: same value, same direction.

Your reasoning for the induced emf is right, too. Since they don't tell us how the I2 comes about, there isn't much more that can be said about the effects.
Thanks for everything thus far. Apparently there's been an error with the question grading, so I'm pretty sure our answer we have come up to is the correct one. Thanks for everything.
 
Back
Top