What is the formula 1/(dS/dE)>>0 and how does it apply?

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Discussion Overview

The discussion revolves around the formula \( \frac{1}{(dS/dE)} \gg 0 \) and its implications in the context of thermodynamics and entropy. Participants explore the relationship between entropy (S), energy (E), and temperature (T), particularly focusing on the conditions under which temperature is defined and the concept of negative absolute temperatures.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants note that the formula relates to entropy and thermodynamics, specifically defining temperature as \( \frac{1}{T} = \frac{dS}{dE} \).
  • It is suggested that the inequality \( T \gg 0 \) indicates that temperature is well above absolute zero.
  • Some participants mention that the definition of temperature assumes that entropy increases with energy, which is generally true in classical thermodynamics.
  • Others introduce the idea that in systems with a discrete number of states, entropy can decrease with energy, leading to the concept of negative absolute temperatures.
  • There is a discussion about the validity of negative temperatures, with some asserting that they are not possible in classical thermodynamics, while others argue that they can occur in quantum systems.
  • One participant expresses gratitude for the clarification provided, indicating a deeper understanding of the topic.

Areas of Agreement / Disagreement

Participants generally agree on the basic relationship between entropy, energy, and temperature, but there is disagreement regarding the existence and implications of negative absolute temperatures, particularly in classical versus quantum contexts.

Contextual Notes

The discussion highlights the limitations of classical thermodynamics in explaining systems with discrete states and the conditions under which negative temperatures might be considered. There are unresolved aspects regarding the implications of these concepts in different physical contexts.

Shaun Harlow
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I am only aware that the formula has to do with entropy/thermodynamics. I could really use the help on how it applies in physics and what the formula is really about.
 
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Shaun Harlow said:
I am only aware that the formula has to do with entropy/thermodynamics. I could really use the help on how it applies in physics and what the formula is really about.

In that equation, S is the entropy and E is the energy. In thermodynamics, temperature can be defined as:

\frac{1}{T} = \frac{dS}{dE}

So your inequality just says T \gg 0. So the temperature is well above absolute zero.
 
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stevendaryl said:
In that equation, S is the entropy and E is the energy. In thermodynamics, temperature can be defined as:

\frac{1}{T} = \frac{dS}{dE}

So your inequality just says T \gg 0. So the temperature is well above absolute zero.

That definition of temperature assumes that entropy increases with energy (so T is always positive), which is true for classical thermodynamics, but for systems with a discrete number of states, it's possible for S to decrease with E, which leads to the bizarre notion of a negative absolute temperature.
 
So the inequality is saying that the temperature is above zero? If so, you talk of the "bizarre notion" of a negative absolute temperature that some people infer, but that is not possible correct?
 
Shaun Harlow said:
So the inequality is saying that the temperature is above zero? If so, you talk of the "bizarre notion" of a negative absolute temperature that some people infer, but that is not possible correct?

The symbol \gg means "much greater than". So the temperature isn't just positive, it's pretty high.

Negative temperatures are not possible in classical thermodynamics, but there are quantum systems where a negative temperature is possible. A negative temperature means that the entropy goes down instead of up when the system gets more energy.
 
stevendaryl said:
That definition of temperature assumes that entropy increases with energy (so T is always positive), which is true for classical thermodynamics, but for systems with a discrete number of states, it's possible for S to decrease with E, which leads to the bizarre notion of a negative absolute temperature.
stevendaryl said:
The symbol \gg means "much greater than". So the temperature isn't just positive, it's pretty high.

Negative temperatures are not possible in classical thermodynamics, but there are quantum systems where a negative temperature is possible. A negative temperature means that the entropy goes down instead of up when the system gets more energy.

Alright! Thank you so much you have helped me better understand this and even went deeper into the meaning without making it hard to understand. I really couldn't thank you enough :)
 

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