- #1
amolv06
- 45
- 0
I need to find the surface area of z=x^{2}+2y where 0\leqx\leq1 and 0\leqy\leq1. I figured it's like trying any other surface area problem, but I think I'm misunderstanding how to set up this problem. Here is what I tried:
\int^{1}_{0}\int^{1}_{0}\sqrt{2x+3}dydx = \frac{5\sqrt{5}}{3}-\sqrt{3}
However, my textbook says the correct answer is (3/2) + (5/8)ln[5]. Any help on where I went wrong would be appreciated.
\int^{1}_{0}\int^{1}_{0}\sqrt{2x+3}dydx = \frac{5\sqrt{5}}{3}-\sqrt{3}
However, my textbook says the correct answer is (3/2) + (5/8)ln[5]. Any help on where I went wrong would be appreciated.
Last edited:
