What Is the Formula of a Mixed Copper Salt Formed with OH- and Br- Ions?

AI Thread Summary
The discussion focuses on determining the formula of a mixed copper salt formed from Cu2+, OH-, and Br- ions. Participants calculate the moles of OH- from the NaOH solution and the moles of Cu from the CuBr2, clarifying that each CuBr2 molecule contains two Cu atoms. There is confusion regarding the presence of water in the CuBr2 formula, with participants debating whether it is a hydrate. The analogy of counting bicycles and tires is used to explain the relationship between moles of CuBr2 and Cu atoms, although it leads to some misunderstanding. Ultimately, the conversation emphasizes the importance of correctly interpreting the chemical formulas and their implications in stoichiometry.
wcbryant87
Messages
14
Reaction score
0

Homework Statement



Cu2+OH-, and Br- form a mixed salt formula Cux(OH)yBrz. In an experiment to determine the values of x, y, and z in the formula of this compound, .760 g CuBr2 (223.4 g/mol) was dissolved in water and reacted with 10.22 ml 0.555M NaOH. Assume that in this reaction, all of the Cu2+ from the CuBr2 and all of the OH- from the NaOH were incorporated into the product but that not all of the Br- was used.

Calculate the number of moles of Cu2+ and OH- in the product.



Homework Equations





The Attempt at a Solution


10.22mL * 1/1000L * .555M NaOH = .00567 mols OH-
I think that is right...but it's finding the moles of Cu that is stumping me.

.760g CuBr2 * 2H2O * 1/259.4 = .00293 mol CuBr2

Now I don't know how to get from that to mols of just Cu. I don't have a volume or anything.
 
Physics news on Phys.org
.760g CuBr2 * 2H2O * 1/259.4 = .00293 mol CuBr2

2H2O? Two water molecules? Where did they come from?

I don't know how to get from that to mols of just Cu.

If you have a dozen bicycles, how many tires do you have? Two dozen, right?
If you have a dozen molecules of CuBr2, how many atoms of Cu do you have? Two dozen.

A mol is just a quantity. Like dozens.

So if you have a mol of CuBr2 molecules, how many moles of Cu do you have?
 
alxm said:
2H2O? Two water molecules? Where did they come from?



If you have a dozen bicycles, how many tires do you have? Two dozen, right?
If you have a dozen molecules of CuBr2, how many atoms of Cu do you have? Two dozen.

A mol is just a quantity. Like dozens.

So if you have a mol of CuBr2 molecules, how many moles of Cu do you have?

The 2H2O is because it's a hydrate.

You kind of lost me on the dozen analogy though. If you have a dozen CuBr2 molecules wouldn't that just be a dozen Cu atoms?
 
wcbryant87 said:
If you have a dozen CuBr2 molecules wouldn't that just be a dozen Cu atoms?

Yes, that's probably what alxm meant.

Why do you think CuBr2 is hydrated? Judging from the molar mass given it is not.
 
wcbryant87 said:
The 2H2O is because it's a hydrate.

Do you know that? Typically these problems would include that information if it was needed, e.g. by writing CuBr2*2H2O.

You kind of lost me on the dozen analogy though. If you have a dozen CuBr2ical molecules wouldn't that just be a dozen Cu atoms?

Whoops, my mind must've slipped. Yes, a dozen Cu and two dozen Br.
(Typical.. screwing up a perfectly simple analogy)
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Back
Top