What is the general solution for b_r here ?

[mmzaj]

\sum^{\infty}_{r=0}\frac{Tb_r}{r+n+1} = {[\sum^{\infty}_{r=0}\frac{b_r}{r+1}]}^{n}

T is a constant .

latex needs to be improved deeply :)

 

[mmzaj]

sorry , this is the correct formula .


\sum^{\infty}_{r=0}\frac{b_r}{r+n+1}={[\sum^{\infty}_{r=0}\frac{b_r}{r+2}]}^{n}

 

[mmzaj]

the above is somehow equivalent to :

\int_{T}t^{n}f(t)dt={(\int_{T}tf(t)dt)}^{n}

now f(t) is to be found in general .