What is the height and kinetic energy lost in a projectile-block collision?

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In the projectile-block collision scenario, a 0.20 kg projectile traveling at 3.0 m/s strikes a 1.3 kg block and becomes embedded in it. To determine how high the block rises after the collision, conservation of momentum is applied to find the combined velocity post-impact. Subsequently, the maximum height can be calculated using energy conservation principles. The kinetic energy lost during the collision is found by comparing the initial kinetic energy of the projectile and the final kinetic energy of the block-projectile system. Detailed calculations and relevant equations are necessary to solve for both height and kinetic energy loss.
Ying99

Homework Statement



A projectile traveling vertically strikes a block and stays in it. The mass of the projectile is 0.20kg and its speed is 3.0m/s at the instant of impact. The mass of the block is 1.3kg. Air resistance may be neglected.

(a) How high does the block rise?
(b) How much kinetic energy is lost in the collision?[/B]
 
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Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
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