What is the Inductance of the Coil in a Radio Tuning Circuit?

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The discussion revolves around calculating the inductance of a coil in a radio tuning circuit using the formula f = 1/(2π√(LC)). Given a maximum current at a capacitance of 300pF and a frequency of 40kHz, the correct inductance is determined to be 52.8mH. A calculation attempt resulted in an incorrect answer due to a misunderstanding of unit conversion, specifically misplacing the exponent in the final result. The key takeaway emphasizes the importance of careful unit management in inductance calculations. Accurate calculations are crucial for effective tuning in radio circuits.
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Inductance of the coil??

Homework Statement


A radio has a tuning circuit consisting of a variable capacitor and antenna coil. IF the circuit has a maximum current when C=300pF and f=40kHz, what's the inductance of the coil??


Homework Equations



f= 1/(2pi root (LC))



The Attempt at a Solution



L=[1/(2pi(40000))]^2 times 1/(300E-12)

But, I didn't get the answer :52.8x 10^3 was the answer;;
 
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The right answer is 52.8x10^(-3) H.

ehild
 
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