What is the initial momentum of the car and rider in a collision?

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The initial momentum of the car is calculated as 45,000 kg m/s, derived from its mass of 1500 kg and speed of 30 m/s. The rider's initial momentum also depends on their mass, which can be determined by converting their weight in pounds to kilograms. The change in momentum for the car is -45,000 kg m/s, indicating a complete stop after the collision. The change in momentum for the rider follows the same principle, with the mass affecting the final calculation. This analysis confirms the relationship between mass, speed, and momentum in a collision scenario.
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Homework Statement


You are riding in a car that crashes into a solid wall. The car comes to a complete stop without bouncing back. The car has a mass of 1500 kg and has a speed of 30 m/s before the crash.

What is the car’s initial momentum? What is your initial momentum? (Recall that the weight
of one kilogram is 2.2 lbs) What is the change in the momentum of the car? What is the
change in your momentum?

Homework Equations


The Attempt at a Solution



CarI= (1500kg) X (30m/s)= 45000kg m/s
YouI=(Mass) X (30 m/s)

Car change= (1500kg) X (-30m/s)= -45000kg m/s
You change= (Mass) X (-30m/s)
 
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Yes...where your mass in kg is your weight in pounds divided by 2.2.
I guess that is what the problem is asking...
 
That all looks right. Is that all you wanted to know?
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
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