What is the Instantaneous Rate of Change at Noon?

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The discussion focuses on estimating the instantaneous rate of change of temperature at noon based on hourly readings in Whitefish, Montana. Participants suggest that plotting the data and drawing a tangent line can help determine the slope, which represents the instantaneous rate of change. However, they note that the data set may not easily correspond to a specific function for differentiation. An alternative method discussed involves calculating the average temperature change between 11 AM and noon, although this may not provide a precise estimate. Overall, the consensus leans towards using graphical methods to better visualize and estimate the rate of change.
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Homework Statement


Temperature readings T (in degrees celcius) were recorded every hour starting at midnight on a day in april in Whitefish, Montana.The time x is measured in hours from midnight.The data are giving in the table at the left

x(h) T(°C)

0 6.5
1 6.1
2 5.6
3 4.9
4 4.2
5 4.0
6 4.0
7 4.8
8 6.1
9 8.3
10 10.0
11 12.1
12 14.3






Homework Equations



Estimate the instantaneous rate of change at noon.

The Attempt at a Solution


I tried to understand the solution but still don't get it.so could somebody help me?








The Attempt at a Solution

 
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With just that set of data, noon is an endpoint if you plot it. I mean you could find the average temperature change between 11 AM and noon but that would not be a great estimate. I'm not sure what kind of solution you're looking for here. The best way to estimate the instantaneous rate of change is to plot the graph, use a ruler to draw a tangent line, and try figuring out the slope, but with the data set you've given, this won't work out too well.
 
The best way to estimate the instantaneous rate of change is to plot the graph, use a ruler to draw a tangent line, and try figuring out the slope, but with the data set you've given, this won't work out too well.

Thanks!I'll try it.
 
Brunll, you could use the set of points and graph to develop a function, F(x) = something, and perform differentiation on it, and find the value of the derivative at the point where x=12
 
symbolipoint said:
Brunll, you could use the set of points and graph to develop a function, F(x) = something, and perform differentiation on it, and find the value of the derivative at the point where x=12

That data do not easily map to a function.

I would go with the slope of the tangent.

k
 
snipez90 said:
... you could find the average temperature change between 11 AM and noon but that would not be a great estimate.

... The best way to estimate the instantaneous rate of change is to plot the graph, use a ruler to draw a tangent line, and try figuring out the slope, but with the data set you've given, this won't work out too well.

I think the 1st method mentioned here is more accurate than the 2nd method.
 
first convert the data to change in temperature per hour.

next to that make a chart of change in change in temperature per hour.
 
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