The function you mention will never have an inverse.
For example, if f(x,y)=2+x, then f cannot have an inverse since f(0,0)=2=f(0,1). Thus (0,0) and (0,1) are both being sent to 2. But then the inverse needs to send 2 to both (0,0) and (0,1), but this is impossible for a function.
In general, your function is one f:\mathbb{R}^2\rightarrow \mathbb{R}, it can have no (continuous) inverse since otherwise the plane would be homeomorphic to the line. And this cannot be.
If you had a function f:\mathbb{R}^2\rightarrow \mathbb{R}^2 then you might have a continuous inverse. But even then this depends of the function f...
Hi everybody
If we have not any answers for critical points after first partial derivatives equal to zero, how can we continue to find local MAX, local MIN and Saddle point?. For example: Suppose we have below equations for first partial derivatives:
∂ƒ/∂x = y + 5 , ∂ƒ/∂y = 2z , ∂ƒ/∂z = y
As you can see, for ∇ƒ= 0 , there are not any answers (undefined)