What is the Launch Speed of the Package?

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The discussion revolves around calculating the launch speed of a care package fired from a spaceship that comes to a halt after the firing. The initial momentum of the system is determined by the combined mass of the spaceship and the package moving at 124 m/s. After the package is fired, the spaceship's final velocity is zero, allowing for the application of momentum conservation principles. Participants clarify that the launch speed of the package is its final velocity after being fired, which is distinct from its initial velocity. The conversation emphasizes understanding the momentum equations to solve for the package's launch speed effectively.
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Homework Statement



A spaceship is coasting with a constant velocity of 124 m/s. The ship fires a deep space "care package" of mass 1300 kg. The firing of the care package brings the rocket ship to a halt. If the mass of the spaceship, not including the rocket, is 4.0 x 106 kg, what is the launch speed of the package?

Homework Equations



p=mv
ΣPi=ΣPf

PiS=msvs
PiP=mpvp
PfS=msvs
PfP=msvs

ΣPi=PiS+PiP
ΣPf=PfS+PfP

final equation: mSviS+mPviP=mSvfS+mPvfP

where s=spaceship and p=package


The Attempt at a Solution



mS=4.0 x 106 kg
viS=124 m/s
vfS=0
mP=1300 kg
viP=?
vfP=?

I do not know if the final equation used is correctly applied. After plugging in all of the known variables, there are two unknown. Could someone point me in the general direction?

Thank you for your time and help.

-D. Tran
 
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D. Tran said:

Homework Statement



A spaceship is coasting with a constant velocity of 124 m/s. The ship fires a deep space "care package" of mass 1300 kg. The firing of the care package brings the rocket ship to a halt. If the mass of the spaceship, not including the rocket, is 4.0 x 106 kg, what is the launch speed of the package?

Homework Equations



p=mv
ΣPi=ΣPf

PiS=msvs
PiP=mpvp
PfS=msvs
PfP=msvs

ΣPi=PiS+PiP
ΣPf=PfS+PfP

final equation: mSviS+mPviP=mSvfS+mPvfP

where s=spaceship and p=package


The Attempt at a Solution



mS=4.0 x 106 kg
viS=124 m/s
vfS=0
mP=1300 kg
viP=?
vfP=?

I do not know if the final equation used is correctly applied. After plugging in all of the known variables, there are two unknown. Could someone point me in the general direction?

Thank you for your time and help.

-D. Tran

The initial momentum could be written as (mass of package + mass of spaceship)v. The package and spaceship are moving as one to begin with, yes?

All of the above are known.

the final momentum (after the firing or impulse) can be written as you have it and all of the variables are known except the velocity of the package. Which you should now be able to find.
 


pgardn said:
The initial momentum could be written as (mass of package + mass of spaceship)v. The package and spaceship are moving as one to begin with, yes?

All of the above are known.

the final momentum (after the firing or impulse) can be written as you have it and all of the variables are known except the velocity of the package. Which you should now be able to find.

Is finding the initial velocity of the package the same as finding the launch speed?
 


As pgardn has noted, the initial velocity of the spaceship, and the initial velocity of the package, are, with respect to a third party observer, the same. The launch speed is the final velocity of the package v_f (its velocity after it has been fired).
 
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