What is the least amount of force needed to pull a board out from under a box?

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SUMMARY

The discussion focuses on calculating the minimum force required to pull a board out from under a box resting on it. The box has a mass denoted as m1, while the board has a mass denoted as m2, with a length L. The coefficients of static and kinetic friction between the box and the board are critical in determining the force needed, with the static friction coefficient being greater than the kinetic friction coefficient. The equations of motion, including F=ma, are applied to analyze the forces acting on both the box and the board.

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Homework Statement


A small box of mass is sitting on a board of mass and length L . The board rests on a frictionless horizontal surface. The coefficient of static friction between the board and the box is . The coefficient of kinetic friction between the board and the box is, as usual, less than .

Find , the constant force with the least magnitude that must be applied to the board in order to pull the board out from under the the box (which will then fall off of the opposite end of the board).


Homework Equations



F=ma

The Attempt at a Solution



im confused for my force body diagrams
box is m1 and board is m2
for the box i have
Fnet y: n-m1g=0
Fnet x: fk=m1a

for the board i have:
Fnet y: n-(m1+m2)g=0
Fnet x: F-fk=(m1+m2)a
 
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Hello, did you try to sketch FBD?

I thing it might be a problem with Your last line.
 

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