What is the Length of a Curve with a Cubic Equation?

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Homework Help Overview

The discussion revolves around finding the length of a curve defined by the cubic equation y = x^3/a^2 + a^2/12x, specifically between the points a and a/2. The problem involves calculus concepts related to arc length.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to integrate a derived expression for the length of the curve but are encountering difficulties in simplification. There are questions regarding the correct interpretation of the equation's terms, particularly the last term's format. Some participants suggest verifying arithmetic and clarifying any typos in the original statement.

Discussion Status

The discussion is ongoing, with participants providing clarifications and checking each other's work. There is an acknowledgment of potential typographical errors and a suggestion to re-evaluate the arithmetic involved in the integration process.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the amount of guidance provided. There is a focus on ensuring the correct setup of the problem before proceeding with the solution.

applestrudle
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Homework Statement



Find the length of the curve y = x^3/a^2 + a^2/12x

between a and a/2


Homework Equations



Length L = integrate (1+ dy/dx)^2)^0.5

The Attempt at a Solution



I got to

integrate (9x^4/a^2 + 1/2 + a^4/144x^4)^0.5

but I can't simplify it
 
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applestrudle said:

Homework Statement



Find the length of the curve y = x^3/a^2 + a^2/12x

Is that last term supposed to be ##\frac {a^2}{12x}## or ##\frac{a^2x}{12}##?
between a and a/2


Homework Equations



Length L = integrate (1+ dy/dx)^2)^0.5

The Attempt at a Solution



I got to

integrate (9x^4/a^2 + 1/2 + a^4/144x^4)^0.5

but I can't simplify it

Did you leave out the ##1##? It would help if you showed your work.
 
LCKurtz said:
Is that last term supposed to be ##\frac {a^2}{12x}## or ##\frac{a^2x}{12}##?Did you leave out the ##1##? It would help if you showed your work.

the last term is a^2 / (12x) x in the denominator.

yeah i left out the 1, that was a typo.

L = intergrate (1+ (dy/dx)^2)^0.5

thanks
 
applestrudle said:
integrate (9x^4/a^2 + 1/2 + a^4/144x^4)^0.5

Re-check your arithmetic for that first term and you should be able to work out that the quantity under the radical is a perfect square.
 

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