What is the magnetic field produced 2.0 m from a stream of 10 E9 protons/second?

[PhysicsChick]

A stream of protons passes a given point in space at a rate of 10 E9 protons/second. What magnetic field do they produce 2.0 m from the beam?
Kind of know where to start, but not exactly. the current would be
10 E9 multiplied by 1.6 E-19 i think. and then i think i would use
B=(permativity of free space x I)/(2pir) using 2.0 m as r, but I'm not sure. help?

 

[lethe]

Originally posted by PhysicsChick
A stream of protons passes a given point in space at a rate of 10 E9 protons/second. What magnetic field do they produce 2.0 m from the beam?
Kind of know where to start, but not exactly. the current would be
10 E9 multiplied by 1.6 E-19 i think. and then i think i would use
B=(permativity of free space x I)/(2pir) using 2.0 m as r, but I'm not sure. help?

this is correct. go with it.

 

[M98Ranger]

You are on the right track! To find the magnetic field produced by a stream of protons, we can use the formula B = (μ0 x I)/(2πr), where μ0 is the permeability of free space (4π x 10^-7 Tm/A), I is the current (in Amperes), and r is the distance from the beam (in meters).

First, we need to convert the given current from protons/second to Amperes. Since 1 Ampere is equal to 6.25 x 10^18 protons/second, we can calculate the current as (10 x 10^9 protons/second)/(6.25 x 10^18 protons/second) = 1.6 x 10^-9 A.

Next, we can plug in the values into the formula: B = (4π x 10^-7 Tm/A x 1.6 x 10^-9 A)/(2π x 2.0 m) = 1.0 x 10^-16 T.

Therefore, the magnetic field produced 2.0 m from the beam is 1.0 x 10^-16 T.