What is the magnitude of the force of repulsion between them?

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Homework Help Overview

The problem involves two point charges that repel each other, with a focus on how the force of repulsion changes when the distance between them is altered. The subject area pertains to electrostatics and the application of Coulomb's law.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formula for the force of repulsion and how changing the distance affects the force. Questions arise about the implications of using a modified distance in the formula.

Discussion Status

The discussion is ongoing, with participants exploring the relationship between distance and force. Some guidance has been offered regarding the use of the modified distance in the formula, but no consensus has been reached on the final answer.

Contextual Notes

Participants are working within the constraints of a homework problem, which may limit the information available for discussion. There is an emphasis on understanding the implications of the distance change on the force calculation.

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Homework Statement



Two point charges are separated by a distance r and repel each other with a force F. If
their separation is reduced to 0.293 times the original value, what is the magnitude of
the force of repulsion between them?

Homework Equations





The Attempt at a Solution

 
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What would your approach be here?
 
0.293 + r+F= r+ 0.293?
 
Based on what formula?
 
F= Keq/r sqed
 
So F = k*qq/r2

They want you to use .293*r instead or r

What effect does that have on F?
 
F is consider the electric field force
 
Yes.

So what's the answer?
 
F = k*qq/r2 F= 8.99x 10^9 * (1.6x 10 ^-19 ) sqed divide by .293 = 2.68x 10^ -27,
 
Last edited:

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