What is the magnitude of the magnetic field B in an infinite sheet of current?

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Homework Help Overview

The problem involves determining the magnitude of the magnetic field generated by an infinite sheet of current, specifically focusing on the configuration of the current and the application of Ampere's Law. The subject area relates to electromagnetism and magnetic fields.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the setup of the problem, including the orientation of the current and the expected direction of the magnetic field. There are attempts to apply Ampere's Law, with some participants questioning the choice of the Amperian loop and the integration process.

Discussion Status

The discussion is ongoing, with some participants providing hints and guidance regarding the application of Ampere's Law. There are differing approaches being explored, and participants are encouraged to reconsider their methods and assumptions.

Contextual Notes

Participants note the importance of the closed loop chosen for applying Ampere's Law and the need to clarify which parts of the loop contribute to the integral. There is also mention of specific values for current density and dimensions, which may influence the calculations.

Punchlinegirl
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An infinite sheet of current, perpendicular to the y-axis is located at y=0. The linear current density [tex]\lambda_+_x[/tex] flows in the +x direction. By inspection, we expect the magnetic field direction B_y, on the positive y side of the sheet to be in the +z direction while the magnetic field on the negative y side of the sheet to be in the -z direction. We choose the Amperican loop as the dashed line with sides of length L and w. The magneto motive force is given by 2LB and the current enclosed is [tex]\lambda_+_x * L[/tex].
Let L=0.5 m, w=0.078 m, [tex]\lambda_+_x[/tex]= 1.89 A/m. Find the magnitude of the magnetic field B. Answer in units of T.

I really have no idea how to do this problem. Can someone help? Thanks
 
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Hint: Ampere's Law.
Read the question again. Towards the end of the question, there is a big hint given on what closed loop to take.
 
Ok so the loop I use has sides L and W.
I know that Ampere's Law says B*ds*cos theta= [tex]\mu[/tex]*I
So to get B I divide [tex]\mu[/tex] *I by 2L+2W since you use the perimeter of the square.
So its (1.25e-6)(0.5)(1.89)/ (2*0.5)+(2*.078)

Am I going about this in the right way?
 
I advise you start over from the beginning.

Fist, draw the sheet, the current, the field direction above and below, and the closed amperian loop.

Now, when you integrate over the closed loop, you will be able to see what part contributes to the integral and what part doesn't.
 

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