What is the maximum distance of projectile?

AI Thread Summary
To determine the maximum distance of a projectile, a strategy must be devised that considers conserved quantities such as momentum and energy. Key variables needed include the initial velocity and launch angle, which can be analyzed using the equation d = (v₀²/g)sin(2θ). The discussion raises questions about whether a second launch will achieve the same distance as the first, prompting considerations of factors like air resistance and launch conditions. Proper formatting for equations is emphasized to ensure clarity in communication. Understanding these principles is crucial for accurately solving projectile motion problems.
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Homework Statement
Out of a low, resting cart we shoot a small ball with a mass 5 times smaller than the mass of the cart. The maximum distance of projectile is 10 m. The we let the cart go, so that it can move. What is the maximum distance of projectile in this case? Under what angle does the ball hit the ground in each cases?
Relevant Equations
$d={\frac {v_{0}^{2}}{g}}\sin(2\theta )$
$G=mv$
I don't know how to begin.
 
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You begin by devising a strategy. I will get you started. What quantities do you think are conserved throughout the launching of the projectile? What quantities do you need to know in order to answer the questions? Do you expect the projectile in the second launch go as far as in the first launch? Why or why not?

For future reference: "I don't know where to begin" is not an acceptable attempt. You must show an effort to answer the question even if it is incomplete or incorrect.
 
The relevant equation $d={\frac {v_{0}^{2}}{g}}\sin(2\theta )$ is apparently formatting language for how you are viewing the problem. It did not translate well to Physics Forums. Please enter it so it is understandable to us.

Now I will give a tip: what do you know about how the principle of conservation of momentum affects the center of mass?
 
sojsail said:
The relevant equation $d={\frac {v_{0}^{2}}{g}}\sin(2\theta )$ is apparently formatting language for how you are viewing the problem. It did not translate well to Physics Forums. Please enter it so it is understandable to us.
Second that. Use two dollar sign, $$, instead of one to bracket your expression and it should work fine. For in-line expressions, use ## at each end.
 
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