What is the Maximum Error in Predicting Solar Eclipse Times on Jupiter?

  • Thread starter Thread starter sparkle123
  • Start date Start date
  • Tags Tags
    Eclipse Solar
AI Thread Summary
The discussion focuses on calculating the maximum error in predicting solar eclipse times on Jupiter as observed from Earth, particularly due to the relative positions of the two planets. The maximum error identified is 2.6 x 10^3 km, which arises when Earth and Jupiter are aligned. Participants clarify that the solar eclipse involves a moon of Jupiter passing in front of the Sun, casting a shadow on Jupiter that can be observed from Earth. There is a request for guidance on how to approach the problem further, highlighting the need for additional information about Jupiter's radius. The conversation emphasizes the importance of considering planetary alignment in eclipse predictions.
sparkle123
Messages
172
Reaction score
0
Solar Eclipse Problem (a math problem, not about astronomy)

Homework Statement



To a good approximation, Earth and Jupiter move around the
Sun in circular orbits of 1.49 x 108 km and 7.79 x 109 km
radius, respectively. What is the maximum error that can
arise in the prediction of solar eclipse times (as observed from
Earth) on Jupiter caused by one of its moons if one fails to
take into account the variation of the relative position of the
two planets?

Answer: 2.6 x 103

Homework Equations



radius of earth: 6.37 x 103 km

The Attempt at a Solution



I think error happens when Earth and Jupiter are aligned. But the radius of Jupiter is not given. Please help!

Thanks!
 
Last edited:
Physics news on Phys.org
hi sparkle123! :smile:

the solar eclipse means the moon of Jupiter passing in front of the sun,

which we can tell from Earth because we see the shadow of the moon passing across Jupiter :wink:
 
Thanks tiny-tim! :)
Could you please give some advice on how to proceed?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
10
Views
2K
Replies
2
Views
3K
Replies
7
Views
6K
Replies
1
Views
5K
Replies
22
Views
3K
Back
Top