What is the Maximum Height Attained by an Object Launched from Earth's Surface?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 4K views
GOsuchessplayer
Messages
9
Reaction score
0

Homework Statement


An Object is fired vertically upward from the surface of the Earth ( of radius RE ) with an initial speed vi that is comparable to but less than the escape speed vesc

Show that the object attains a maximum height h given by h=[tex]\stackrel{R_{E}v^{2}_{i}}{v^{2}_{esc}-v^{2}_{i}}[/tex]

Homework Equations


The Attempt at a Solution


I have the solution but I am confused with a step.
Here is the solution provided up until the step on which I am confused:

[tex](K+U_{g})_{f}[/tex]=[tex](K+U_{g})_{f}[/tex]

[tex]\stackrel{1}{2}[/tex]m[tex]v^{2}_{i}[/tex] - [tex]\stackrel{GmM_{E}}{R_{E}}[/tex] = 0 - [tex]\stackrel{GmM_{E}}{R_{E}+h}[/tex]

where [tex]\stackrel{1}{2}[/tex]m[tex]v^{2}_{esc}[/tex]= [tex]\stackrel{GmM_{E}}{R_{E}}[/tex]

Then[tex]\stackrel{1}{2}[/tex][tex]v^{2}_{i}[/tex] - [tex]\stackrel{1}{2}[/tex][tex]v^{2}_{esc}[/tex]= -[tex]\stackrel{1}{2}[/tex][tex]v^{2}_{esc}[/tex] ([tex]\stackrel{R_{E}}{R_{E}+h}[/tex])

So the jump I am confused about is the equation that follows the "Then" Statement. I'm not sure why this is true.

(sorry for the poor look of the equations. Hopefully its readable, I wasn't sure how to make fractions.)
 
Last edited:
Physics news on Phys.org
\frac x y

[tex]\frac x y[/tex]

And if not absolutely necessary don't put LaTeX inline, it looks better in its own lines.