What Is the Maximum Kinetic Energy of a 2kg Body Moving Along the X-Axis?

AI Thread Summary
The discussion centers on calculating the maximum kinetic energy of a 2kg body moving along the x-axis under the influence of a force defined by F=(12-2x) N. The kinetic energy formula, KE=mv^2, is referenced, with a velocity of 5.5 m/s at x=2m. Questions arise regarding the force at x=0, the point where the force becomes zero, and whether the force changes linearly. The conversation also explores calculating the average force, the work done over the distance, and equating this work to the kinetic energy gained by the mass. Ultimately, the participants seek clarity on the correct kinetic energy value, with one suggesting it is 46J.
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1.the only force acting on a 2kg body as it moves along the x-axis is given by F=(12-2x)N where x is in m. the velocity of the body at x=2m is 5.5i m/s. what is the maximum kinetic energy attained by the body?




2. KE= mv^2



3. My friend said the answer is 46J but I am not sure how he got it
 
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Looks like there's something wrong with this question.

What is the force experienced by the mass at X=0?
For what value of x does this force disappear?
Does this force change in a linear fashion?
If so, what's the average force on the mass?
Now do we know the average force and the distance over which it operated?
How much work was done?
Can I equate this quantity of work to the kinetic energy received by the mass?

What was the force at x=2m?
What was the average force over the first two metres?
How much work was done in the first two metres?
What was the speed of the mass at two metres?
 

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