What is the Maximum Load a 1.5 m Copper Wire with 1.1 mm Radius Can Suspend?

  • Thread starter Thread starter mikefitz
  • Start date Start date
  • Tags Tags
    Load Max
AI Thread Summary
The discussion centers on calculating the maximum load a 1.5 m copper wire with a radius of 1.1 mm can support without breaking. The elastic limit of copper is noted as 3 × 10^8 Pa, and the tensile strength is 4.2 × 10^8 Pa. The calculation attempts to determine the force per area (F/A) and equate it to the elastic limit, leading to a calculated load of approximately 116,248,535 N. Participants express skepticism about this result, suggesting that the calculated load seems excessively high. The conversation seeks clarification on potential errors in the calculations.
mikefitz
Messages
155
Reaction score
0
What is the maximum load that could be suspended from a copper wire of length 1.5 m and radius 1.1 mm without breaking the wire? Copper has an elastic limit of 3 × 108 Pa and a tensile strength of 4.2 × 10^8 Pa

F/A<Elastic Limit

= m(9.81) / 3.8013 = 3x10^8Pa
9.81m= 114 098 123
m= 116 248 535 N ?

Seems like an aweful lot of load, what did i do wrong on this one?
 
Physics news on Phys.org
any ideas? I worked it out one more time with the same result...
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

What is the Maximum Load a Copper Wire Can Support?
Replies
1
Views
4K
Breaking Point for a Copper Wire
Replies
4
Views
16K
Youngs Modulus. Copper wire experiment
Replies
7
Views
31K

Hot Threads

Recent Insights

Back
Top