What is the maximum period of revolution for a cone filled with water?

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Homework Help Overview

The problem involves a cone filled with water and seeks to determine the maximum period of revolution while ensuring the water does not fall out. The context is rooted in dynamics and circular motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss calculating the minimum velocity at the top of the cone and relate it to the period of revolution using angular velocity formulas. There is confusion about the correct approach and the application of relevant equations.

Discussion Status

Several participants are exploring different methods to find the period of revolution, including using centripetal acceleration and angular velocity. There is acknowledgment of confusion regarding the formulas and their application, but no consensus has been reached on a definitive approach.

Contextual Notes

Participants express uncertainty about the movement dynamics and the conditions under which the water remains in the cone. There are mentions of potential errors in applying formulas and the need for dimensional analysis.

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Homework Statement


A SMALL CONE FILLED WITH WATER OF RADIUS 4M AND THE WATER DOESNT FALL DOWN. WHAT MUST BE THE MAXIMUM PERIOD OF REVOLUTION


Homework Equations





The Attempt at a Solution



I AM CONFUSED!

HOW TO APPROACH THE PROBLEM? SHOULD FIRST CALCULATE THE MINIMUM VELOCITY AT TOP AND THEN FIND OUT THE t USING W=2PIE/T? (the answer is not cuming using this approach
 
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hi vipulgoyal! :smile:

(have an omega: ω and a pi: π :wink:)

is this movement in a vertical circle?

the water will fall out if the reaction force is zero …

use F = ma and centripetal acceleration :smile:
 


the speed at the top is √gl now have to find time period

the answer doest come by this method ω= 2π /T
ω =r x v
 
hi vipulgoyal! :smile:

(just got up :zzz: …)
vipulgoyal said:
the speed at the top is √gl now have to find time period

yup! :biggrin:
the answer doest come by this method ω= 2π /T
ω =r x v

("doest"? :confused:)

nooo :redface: …

v = ωr :rolleyes:​
 


yeah thnx... i always get mixed up in these formulas...
 
me too :redface:, so i check by using dimensions :-p …

v is L/T, r is L, ω is 1/T :wink:​
 

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