What is the Mesh Current Analysis for Finding i0 in a Circuit?

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SUMMARY

The discussion focuses on using mesh current analysis to find the current i0 in a given circuit with a 3A current source. The participants detail the application of Kirchhoff's Voltage Law (KVL), Kirchhoff's Current Law (KCL), and Ohm's Law in their calculations. The initial equations derived for currents i1, i2, and i3 were corrected after identifying algebraic errors, leading to the conclusion that i0 is calculated as i2 - i1. The final values for i1, i2, and i3 were found to be -1.09A, -2.945A, and 0.054A respectively, with the expected value for i0 being -1.73A.

PREREQUISITES
  • Understanding of mesh current analysis
  • Familiarity with Kirchhoff's Voltage Law (KVL)
  • Knowledge of Kirchhoff's Current Law (KCL)
  • Proficiency in applying Ohm's Law
NEXT STEPS
  • Review mesh current analysis techniques in electrical circuits
  • Practice solving circuit problems using KVL and KCL
  • Explore common mistakes in circuit analysis and how to avoid them
  • Learn about supermesh concepts and their applications in complex circuits
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing electrical circuits using mesh current analysis.

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Homework Statement


Find i0 in http://images3a.snapfish.com/232323232%7Ffp73395%3Enu%3D52%3A%3A%3E379%3E256%3EWSNRCG%3D3359%3B24399347nu0mrj" using mesh current analysis.

Note that the ^i1, ^i2 and ^i3 are to label my currents and show they are flowing clockwise. i0--> is the direction of the i0 current. The current source is 3A.

Homework Equations



KVL
KCL
Ohm's law

The Attempt at a Solution



So i know that the current sources makes a supermesh and that you basically remove it from the circuit and do mesh analysis 'around the path of the supermesh' and you will get a constraint equation from the supermesh for your 3rd equation.

So for i1 I got:

2i_{1} + 6 + 4(i_{1}-i_{3})+ (i_{1}-i_{2}) = 0

2i_{1} + 4i_{1} - 4i_{3} + i_{1} - i_{2} = -6

8i_{1} - i_{2}-4i_{3}=-6

So the supermesh i got:

5i_{2} + (i_{2}-i_{1}) + 4(i_{3}-i_{1})+12=0

5i_{2} + i_{2} - i_{1} + 4i_{3}-4i_{1}=-12

-5i_{1} + 6i_{2} + 4i_{3} = -12

and the constraint equation:

i_{3}=i_{2}+3

0i_{1}-i_{2}+i_{3} = 3

which makes a 3x4 matrix now i got:

i_{1}=-1.09a

i_{2}=-2.945a

i_{3}=.054a

and i believe that i0 in the circuit should be i2-i1 but they are looking for -1.73a for i0 which is close to but not what you get with my numbers so where did I go wrong?

thanks!
 
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In eq1, I think it should be 7 I1 shouldn't it? You have 8 I1
 
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bah I hate when that happens, now it works out! Those small algebra mistakes really bite you in circuit analysis huh? lol

Thanks though vk6kro
 

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