What is the mistake in my derivative calculation and how can I fix it?

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It's crazy, I don't see where I goes wrong. Lookit..
\frac{\partial}{\partial x} \left(\frac{x}{z\left(\sqrt{x^2+y^2} +\frac{\sqrt{x^2+y^2}^3}{z^2}\right)} \right)
= \left(\frac{1}{z\left(\sqrt{x^2+y^2} +\frac{\sqrt{x^2+y^2}^3}{z^2}\right)} \right)
+(x/z)(-1)\left(\sqrt{x^2+y^2} +\frac{\sqrt{x^2+y^2}^3}{z^2}\right)^{-2}\left((1/2)(x^2+y^2)^{-1/2}2x+(1/z^2)(3/2)\sqrt{x^2+y^2}2x\right)
= \left(\frac{1}{z\left(\sqrt{x^2+y^2} +\frac{\sqrt{x^2+y^2}^3}{z^2}\right)} \right)
-\frac{3x^2\sqrt{x^2+y^2}}{z^3\left(\sqrt{x^2+y^2} +\frac{\sqrt{x^2+y^2}^3}{z^2}\right)^2}
-\frac{x^2}{z\sqrt{x^2+y^2}\left(\sqrt{x^2+y^2} +\frac{\sqrt{x^2+y^2}^3}{z^2} \right)^2}

The first term agrees with Mapple but not the second and third.
In the second, the 3 is a 2 and in the third, the big parenthesis is not raised to the 2. (it's to the 1)

I have checked using the command 'simplify' that our two expressions are not equivalent. what Mapple does is that it get a (x²+y²)^½ out of the parenthesis before taking the derivative. And the worst thing is, when I do that too, I get the same result as mapple, but not when I don't take out (x²+y²)^½ first. I've banged my head on the desk for hours on this and get's see why I don't get the same answer by the two "methods". Help me obi-wan kenobi. You are my only hope.
:cry: :cry: :cry:
 
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quasar987 said:
-\frac{x^2}{z\left(\sqrt{x^2+y^2} +\frac{\sqrt{x^2+y^2}^3}{z^2} \right)^2}
It seems that this term is wrong. I get:
- \frac{x ^ 2}{z\sqrt{x ^ 2 + y ^ 2} \left( \sqrt{x ^ 2 + y ^ 2} + \frac{\sqrt{x ^ 2 + y ^ 2} ^ 3}{z ^ 2} \right) ^ 2}
*You seem to forget a \sqrt{x ^ 2 + y ^ 2} in the denominator...*
You should check it again :wink:
 
Here's what I got

For that term, I get -\frac{x^2}{z\sqrt{x^2+y^2}\left(\sqrt{x^2+y^2} +\frac{\sqrt{x^2+y^2}^3}{z^2} \right)^2}

When I simplify that term I get -\frac{x^2}{\left( x^2+y^2\right)^{\frac{3}{2}} \left( x^2+y^2+z^2\right)^2}


I attached a Maple worksheet with my work (I use Maple v9.51) rename the file without the .txt so it ends with .mw (PF wouldn't let me upload .mw files, but .txt OK).
 

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VietDao: you'Re right, but it was just a Latex error. I have that too and haver edited the original post.

I still don't see where my mistake is.
Here's what my mapple has to say:
 

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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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