What is the Molarity of an Acid Sample Neutralized by NaOH?

Thread starter kara
Start date Oct 12, 2006
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Acid standardization

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To find the molarity of the acid sample, the neutralization reaction between H2SO4 and NaOH is considered. It is established that 46.5 mL of 0.215M NaOH is needed to neutralize 15.0 mL of H2SO4. The calculation involves determining the moles of NaOH used and applying the stoichiometry of the reaction to find the moles of H2SO4. Finally, the molarity of the acid is calculated using the formula M = moles of solute/liters of solution. The problem is resolved successfully, demonstrating the application of molarity concepts in acid-base neutralization.

Oct 12, 2006

kara

It requires 46.5 mL of 0.215M NaOH to neutralize 15.0 mL of aqueous H2SO4. What was the molarity (M) of the acid sample?

I'm not quite sure how to approach this quesiton, if anyone has and starter tips please let me know.

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Oct 12, 2006

kara

So for a I know that M (molarity) = moles of solute/liters of sol'n

Oct 12, 2006

kara

Don't worry about it, I figured it out :D

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