What Is the Molarity of an Isotonic Saline Solution?

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Isotonic saline solutions must match the osmotic pressure of blood, which is approximately 7.7 atm at 25°C. The molarity of an isotonic saline solution can be calculated using the modified equation π = iMRT, where i represents the van't Hoff factor. For sodium chloride (NaCl), which dissociates into two ions (Na+ and Cl-), the van't Hoff factor is 2. By substituting i with 2, the calculation can proceed to determine the molarity required for isotonicity. Understanding the van't Hoff factor is crucial for accurately calculating the molarity of electrolytic solutions.
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Aqueous solutions introduced into the bloodstream by injection must have the same osmotic pressure as blood; that is, they must be "isotonic" with blood. At 25C, the average osmotic pressure of blood is 7.7 atm. What is the molarity of an isotonic saline solution (NaCl in H2O)? Recall that NaCl is an electrolyte; assume complete conversion to Na and Cl ions.

The equation I have for osmosis is π=MRT (π=pressure, M=molarity, R=constant, T=temperature), but in the text it says this is for nonelectrolytes. I'm not sure where to go with this.
 
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Try looking into something called the van't Hoff factor.
 
The equation you gave can be converted to the osmosis equation for associating/dissociating solutes by multiplying the RHS with a factor 'i' (Also Called the Van't Hoff Factor)

So it becomes

Pi=iMRT

i is a factor defined as the number of particles after association/dissocation divided by the number of particles before it. One particle of NaCl Dissociates into two particles, The Sodium Ion and the Chloride Ion, so van't hoff factor for it is 2. replace i by 2 and proceed as usual.
 
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