What is the Moment of Inertia of a Hollow Sphere?

Click For Summary

Homework Help Overview

The discussion revolves around determining the moment of inertia of a hollow sphere, particularly focusing on the implications of having an inner radius and thickness. Participants explore the definitions and mathematical approaches relevant to this topic in classical mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need for clarity regarding the thickness of the hollow sphere and whether it is treated as a shell. Questions about integration methods and the setup of limits in spherical coordinates are raised. Some participants suggest using known moments of inertia of solid spheres and concentric shells to approach the problem.

Discussion Status

The conversation is ongoing, with various interpretations being explored. Some participants have offered guidance on how to approach the integration process, while others have pointed out the need for clearer definitions. There is no explicit consensus on the method to be used, but several productive lines of reasoning are being examined.

Contextual Notes

Participants mention constraints such as only knowing the mass of the outer part of the sphere and the implications of defining a hollow object. There are also references to the common usage of terms in mathematics that may affect understanding.

flash
Messages
66
Reaction score
0
The moment of inertia of a sphere rotating about the centre is (2/5)mr^2, but what if it has a hollow 'core'?
 
Last edited:
Physics news on Phys.org
You'll need to be more specific. Is it a shell with negligible thickness? Are we considering an inner radius? Do you know how to integrate to find moment of inertia?
 
A (2-)sphere is hollow to begin with. So your question doesn't make too mush sense.

Daniel.
 
Sorry, I should have been clearer. There is an inner radius involved, so the thickness is not negligable. I know the basic idea of integration to find the moment of inertia, r^2dm, but haven't done much of it.
 
This problem is classical on PF. You should use the search option and I'm sure you'll get satisfied.

Daniel.
 
Okay, so you want to find the moment of a spherical SHELL (can you accept that wording, dexie?).

Now, described in spherical coordinates, set up the limits of integration for the three variables first!
 
flash said:
Sorry, I should have been clearer. There is an inner radius involved, so the thickness is not negligable. I know the basic idea of integration to find the moment of inertia, r^2dm, but haven't done much of it.

You can do it with integration, or just take advantage of the fact that calculating the moment of inertia is just an addition problem. The moment of inertia of a solid sphere (known) is the sum of the moments of inertia of a smaller inner sphere plus the moment of inertia of a concentric outer spherical shell.
 
dextercioby said:
A (2-)sphere is hollow to begin with. So your question doesn't make too mush sense.

Daniel.

Therefore the volume of a sphere is zero. Even mathematicians resort to "common usage" when it serves their purpose. I've never heard anybody say "the volume of the region bounded by a shpere of radius R" is . . . .

We of course are making the same mistake when we talk about the area of a circle. Using its formal definition, it has none.
 
Last edited:
Is a box hollow or filled, I wonder? :confused:

And what about the prolate spheroids and the parallellepipedes in the world?
 
  • #10
Thanks for all the replies. I only know the mass of the outer part of the sphere. Here's what I think I will do: Find the density of the outer part, calculate the moment of inertia of the solid sphere with this density and subtract the moment of inertia of the inner sphere with this density. Will that work?
 
  • #11
flash said:
Thanks for all the replies. I only know the mass of the outer part of the sphere. Here's what I think I will do: Find the density of the outer part, calculate the moment of inertia of the solid sphere with this density and subtract the moment of inertia of the inner sphere with this density. Will that work?

C'est parfait! Yes.
 
  • #12
Cool, thanks.
 
  • #13
OlderDan said:
Therefore the volume of a sphere is zero. Even mathematicians resort to "common usage" when it serves their purpose. I've never heard anybody say "the volume of the region bounded by a shpere of radius R" is . . . .

We of course are making the same mistake when we talk about the area of a circle. Using its formal definition, it has none.

Of course you didn't hear that, simply because they use the word "ball".

Daniel.
 
  • #14
I use the word sphere. =)
 

Similar threads

Replies
16
Views
4K
  • · Replies 40 ·
2
Replies
40
Views
6K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
11
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 11 ·
Replies
11
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
2K
Replies
8
Views
14K
  • · Replies 21 ·
Replies
21
Views
3K