flash
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The moment of inertia of a sphere rotating about the centre is (2/5)mr^2, but what if it has a hollow 'core'?
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The discussion revolves around determining the moment of inertia of a hollow sphere, particularly focusing on the implications of having an inner radius and thickness. Participants explore the definitions and mathematical approaches relevant to this topic in classical mechanics.
The conversation is ongoing, with various interpretations being explored. Some participants have offered guidance on how to approach the integration process, while others have pointed out the need for clearer definitions. There is no explicit consensus on the method to be used, but several productive lines of reasoning are being examined.
Participants mention constraints such as only knowing the mass of the outer part of the sphere and the implications of defining a hollow object. There are also references to the common usage of terms in mathematics that may affect understanding.
flash said:Sorry, I should have been clearer. There is an inner radius involved, so the thickness is not negligable. I know the basic idea of integration to find the moment of inertia, r^2dm, but haven't done much of it.
dextercioby said:A (2-)sphere is hollow to begin with. So your question doesn't make too mush sense.
Daniel.
flash said:Thanks for all the replies. I only know the mass of the outer part of the sphere. Here's what I think I will do: Find the density of the outer part, calculate the moment of inertia of the solid sphere with this density and subtract the moment of inertia of the inner sphere with this density. Will that work?
OlderDan said:Therefore the volume of a sphere is zero. Even mathematicians resort to "common usage" when it serves their purpose. I've never heard anybody say "the volume of the region bounded by a shpere of radius R" is . . . .
We of course are making the same mistake when we talk about the area of a circle. Using its formal definition, it has none.