What is the momentum of an object on an incline?

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AI Thread Summary
The discussion centers on calculating the momentum of an object on an incline, specifically a 5 kg box being pulled up a hill with a constant force. The momentum is determined using the formula p=mv, leading to a calculated value of 10 kg-m/s when considering the object's mass and velocity. However, there is confusion regarding the distinction between momentum and the rate of change in momentum, which requires different considerations. The focus is clarified to be on the magnitude of momentum rather than its rate of change. The final answer confirmed is 10 kg-m/s for the magnitude of the momentum.
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Homework Statement



A 20-Newton force pulling an object up a hill at a constant rate of 2 m/s. The diagram shows a box that is 5 kg on an incline that is 30 m long and 10 m high.

the answers are
1) 0 kg-m/s
2) 10 kg-m/s
3) 100 kg-m/s
4) 600 kg-m/s

The equation for momentum is p=mv

Homework Equations





The Attempt at a Solution



so wouldn't i just do
(5 Kg)(2 m/s)= 10 kg-m/s
 
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yes, if the question is "what is the magnitude of the momentum"
... but for "what is the rate of change in momentum", the answer is different .
 
yes it was what is the magnitude of the momentum?
thank you :)
 
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